Select the correct answer.

Which calculation correctly uses prime factorization to write [tex]$\sqrt{48}$[/tex] in simplest form?

A. [tex]$\sqrt{48}=\sqrt{2 \cdot 2 \cdot 2 \cdot 2 \cdot 3}=2 \sqrt{12}$[/tex]

B. [tex][tex]$\sqrt{48}=\sqrt{4 \cdot 12}=2 \sqrt{12}$[/tex][/tex]

C. [tex]$\sqrt{48}=\sqrt{2 \cdot 2 \cdot 2 \cdot 2 \cdot 3}=4 \sqrt{3}$[/tex]

D. [tex]$\sqrt{48}=\sqrt{16 \cdot 3}=4 \sqrt{3}$[/tex]



Answer :

To answer this question, we need to simplify the expression [tex]\(\sqrt{48}\)[/tex] using the method of prime factorization and find which option matches our simplified form.

Let's analyze each given option:

Option A:
[tex]\[ \sqrt{48} = \sqrt{2 \cdot 2 \cdot 2 \cdot 2 \cdot 3} = 2 \sqrt{12} \][/tex]
This statement is incorrect because it stops the simplification too early.

Option B:
[tex]\[ \sqrt{48} = \sqrt{4 \cdot 12} = 2 \sqrt{12} \][/tex]
This statement is incorrect for the same reason as Option A.

Option C:
[tex]\[ \sqrt{48} = \sqrt{2 \cdot 2 \cdot 2 \cdot 2 \cdot 3} = 4 \sqrt{3} \][/tex]
Let's check the simplification here:
- The prime factorization of 48 is [tex]\(2 \cdot 2 \cdot 2 \cdot 2 \cdot 3\)[/tex].
- This can be written as [tex]\(\sqrt{(2 \cdot 2) \cdot (2 \cdot 2) \cdot 3}\)[/tex].
- Simplifying further, [tex]\(\sqrt{(2^2) \cdot (2^2) \cdot 3} = \sqrt{4 \cdot 4 \cdot 3} = 4 \sqrt{3}\)[/tex].

This statement is correct.

Option D:
[tex]\[ \sqrt{48} = \sqrt{16 \cdot 3} = 4 \sqrt{3} \][/tex]
This statement is also correct because:
- [tex]\(16\)[/tex] is the square of [tex]\(4\)[/tex], so it can be pulled out of the square root.
- [tex]\(\sqrt{48} = \sqrt{16 \cdot 3} = \sqrt{16} \cdot \sqrt{3} = 4 \sqrt{3}\)[/tex].

Thus, the correct options are C and D, but if we are to choose only one based on the simplification step shown explicitly, the correct simplified representation in simplest form is [tex]\(\boxed{D}\)[/tex].

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