To solve the given problem, let's analyze the data and calculate the required values step-by-step.
### Step 1: Relative Frequency of Picking Each Toy
Relative frequency is given by the ratio of the number of times a toy is picked to the total number of picks.
#### Red Toy:
- Number of times red toy picked: 30
- Total number of picks: 60
Relative frequency of picking a red toy:
[tex]\[ \text{Relative frequency of red} = \frac{\text{Number of times red picked}}{\text{Total number of picks}} = \frac{30}{60} = 0.5 \][/tex]
#### Green Toy:
- Number of times green toy picked: 3
- Total number of picks: 60
Relative frequency of picking a green toy:
[tex]\[ \text{Relative frequency of green} = \frac{\text{Number of times green picked}}{\text{Total number of picks}} = \frac{3}{60} = 0.05 \][/tex]
### Step 2: Determining the Greatest and Least Number of Toys
To find which toy is likely to be present in the greatest number and which in the least number, we look at the numbers of times each toy was picked. The toy that was picked the most is likely to be present in the greatest quantity, and the toy picked the least is likely to be in the smallest quantity.
- Pink: 9
- Red: 30
- Green: 3
- Blue: 18
The greatest number among these is 30 (red), and the smallest number among these is 3 (green).
### Conclusion
Given the computed values, we fill in the blanks in the question:
The relative frequency of picking up a red toy is 0.5. The relative frequency of picking up a green toy is 0.05. It is likely that the machine has the greatest number of red toys. It is likely that the machine has the least number of green toys.
