Answer :

Sure! Let's find the x-intercept and y-intercept for the linear function given by the equation [tex]\( -4y = 7x + 56 \)[/tex].

### Finding the x-intercept

The x-intercept is found by setting [tex]\( y = 0 \)[/tex] in the equation of the line and solving for [tex]\( x \)[/tex].

1. Substitute [tex]\( y = 0 \)[/tex] into the equation:
[tex]\[ -4(0) = 7x + 56 \][/tex]

2. Simplify the equation:
[tex]\[ 0 = 7x + 56 \][/tex]

3. Solve for [tex]\( x \)[/tex]:
[tex]\[ 7x = -56 \][/tex]

4. Divide both sides by 7:
[tex]\[ x = -8 \][/tex]

So, the x-intercept is [tex]\( x = -8 \)[/tex].

### Finding the y-intercept

The y-intercept is found by setting [tex]\( x = 0 \)[/tex] in the equation of the line and solving for [tex]\( y \)[/tex].

1. Substitute [tex]\( x = 0 \)[/tex] into the equation:
[tex]\[ -4y = 7(0) + 56 \][/tex]

2. Simplify the equation:
[tex]\[ -4y = 56 \][/tex]

3. Solve for [tex]\( y \)[/tex]:
[tex]\[ y = \frac{56}{-4} \][/tex]

4. Simplify:
[tex]\[ y = -14 \][/tex]

So, the y-intercept is [tex]\( y = -14 \)[/tex].

### Summary

The intercepts of the linear function [tex]\( -4y = 7x + 56 \)[/tex] are:
- x-intercept: [tex]\( x = -8 \)[/tex] (so the point is [tex]\( (-8, 0) \)[/tex])
- y-intercept: [tex]\( y = -14 \)[/tex] (so the point is [tex]\( (0, -14) \)[/tex])