What is the weight (in grams) of a liquid that exactly fills a 202 milliliter container if the density of the liquid is [tex]$0.685 \frac{\text{grams}}{\text{milliliter}}$[/tex]? Round to the nearest hundredth when necessary, and only enter numerical values, which can include a decimal point.

Answer for Blank 1:



Answer :

To find the weight of a liquid that fills a 202 milliliter container with a density of [tex]\(0.685 \frac{\text{grams}}{\text{milliliter}}\)[/tex], follow these steps:

1. Identify the volume of the container:
The volume of the container is 202 milliliters.

2. Identify the density of the liquid:
The density of the liquid is [tex]\(0.685 \frac{\text{grams}}{\text{milliliter}}\)[/tex].

3. Calculate the weight of the liquid:
Use the formula for weight, which is:
[tex]\[ \text{Weight} = \text{Volume} \times \text{Density} \][/tex]

Substitute the known values into the formula:
[tex]\[ \text{Weight} = 202 \, \text{ml} \times 0.685 \, \frac{\text{grams}}{\text{ml}} \][/tex]

4. Perform the multiplication:
[tex]\[ \text{Weight} = 202 \times 0.685 = 138.37 \, \text{grams} \][/tex]

5. Round to the nearest hundredth:
The calculated weight is already at the hundredth place, so the weight remains [tex]\(138.37\)[/tex] grams.

The weight of the liquid is:
[tex]\[ \boxed{138.37} \][/tex]