Question:
If a machine is supplied with power at a rate of [tex]$4,000 \, W$[/tex], and it does useful work with a power of [tex]$1,900 \, W$[/tex], what's the efficiency of the machine?

Answer Options:
Select one of four:
A. Efficiency [tex]=2.1\%[/tex]
B. Efficiency [tex]=80\%[/tex]
C. Efficiency [tex]=195\%[/tex]
D. Efficiency [tex]=47.5\%[/tex]



Answer :

To determine the efficiency of the machine, we need to understand the relationship between input power and output power. Efficiency is a measure of how well a machine converts input energy into useful output energy.

The formula for efficiency ([tex]\( \eta \)[/tex]) is given by:
[tex]\[ \eta = \left( \frac{\text{Power Output}}{\text{Power Input}} \right) \times 100 \% \][/tex]

Here, we are given:
- Power Input ([tex]\( P_{in} \)[/tex]) = 4,000 W
- Power Output ([tex]\( P_{out} \)[/tex]) = 1,900 W

Now, substituting these values into the efficiency formula:

[tex]\[ \eta = \left( \frac{1900 \, \text{W}}{4000 \, \text{W}} \right) \times 100 \% \][/tex]

Calculating the fraction:
[tex]\[ \frac{1900}{4000} = 0.475 \][/tex]

Multiplying by 100 to get the percentage:
[tex]\[ 0.475 \times 100 \% = 47.5 \% \][/tex]

Therefore, the efficiency of the machine is [tex]\( 47.5 \% \)[/tex].

Among the given answer options:
- Efficiency [tex]\( = 2.1 \% \)[/tex]
- Efficiency [tex]\( = 80 \% \)[/tex]
- Efficiency [tex]\( = 195 \% \)[/tex]
- Efficiency [tex]\( = 47.5 \% \)[/tex]

The correct answer is:
[tex]\[ \boxed{47.5 \%} \][/tex]