Find [tex]$g(f(x))$[/tex].

[tex]\[
\begin{array}{l}
f(x) = 3x + 2 \quad g(x) = x - 1 \\
g(f(x)) = \Box x + \square
\end{array}
\][/tex]

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Answer :

To find the composite function [tex]\( g(f(x)) \)[/tex], let's proceed step-by-step:

1. Identify the given functions [tex]\( f(x) \)[/tex] and [tex]\( g(x) \)[/tex]:
[tex]\[ f(x) = 3x + 2 \][/tex]
[tex]\[ g(x) = x - 1 \][/tex]

2. Substitute [tex]\( f(x) \)[/tex] into [tex]\( g(x) \)[/tex] to find [tex]\( g(f(x)) \)[/tex]:
[tex]\[ g(f(x)) = g(3x + 2) \][/tex]

3. Substitute [tex]\( 3x + 2 \)[/tex] into the function [tex]\( g(x) \)[/tex]:
[tex]\[ g(3x + 2) = (3x + 2) - 1 \][/tex]

4. Simplify the expression [tex]\( (3x + 2) - 1 \)[/tex]:
[tex]\[ g(3x + 2) = 3x + 2 - 1 \][/tex]

5. Combine like terms:
[tex]\[ g(3x + 2) = 3x + 1 \][/tex]

So, the composite function [tex]\( g(f(x)) \)[/tex] is:
[tex]\[ g(f(x)) = 3x + 1 \][/tex]

In the form [tex]\( ax + b \)[/tex], we have:
[tex]\[ g(f(x)) = 3x + 1 \][/tex]

Thus, [tex]\( a = 3 \)[/tex] and [tex]\( b = 1 \)[/tex].

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