The form of your answer should either be [tex]$p(x)$[/tex] or [tex]$p(x) + \frac{k}{x-2}$[/tex], where [tex][tex]$p(x)$[/tex][/tex] is a polynomial and [tex]$k$[/tex] is an integer.

[tex]\frac{x^3 + 6x^2 - 5x}{x-2} = [/tex]



Answer :

To solve the expression [tex]\(\frac{x^3 + 6x^2 - 5x}{x - 2}\)[/tex], we need to start by performing polynomial long division.

1. Set up the division:

Dividend: [tex]\(x^3 + 6x^2 - 5x\)[/tex]
Divisor: [tex]\(x - 2\)[/tex]

2. First division step:

Divide the leading term of the dividend [tex]\(x^3\)[/tex] by the leading term of the divisor [tex]\(x\)[/tex]. This gives [tex]\(x^2\)[/tex].

Multiply [tex]\(x^2\)[/tex] by [tex]\((x - 2)\)[/tex] to get [tex]\(x^3 - 2x^2\)[/tex].

* Subtract [tex]\(x^3 - 2x^2\)[/tex] from [tex]\(x^3 + 6x^2 - 5x\)[/tex]:
[tex]\[ (x^3 + 6x^2 - 5x) - (x^3 - 2x^2) = (x^3 - x^3) + (6x^2 + 2x^2) - 5x = 8x^2 - 5x \][/tex]

3. Second division step:

Divide the leading term of the new dividend [tex]\(8x^2\)[/tex] by the leading term of the divisor [tex]\(x\)[/tex]. This gives [tex]\(8x\)[/tex].

Multiply [tex]\(8x\)[/tex] by [tex]\((x - 2)\)[/tex] to get [tex]\(8x^2 - 16x\)[/tex].

* Subtract [tex]\(8x^2 - 16x\)[/tex] from [tex]\(8x^2 - 5x\)[/tex]:
[tex]\[ (8x^2 - 5x) - (8x^2 - 16x) = (8x^2 - 8x^2) + (16x - 5x) = 11x \][/tex]

4. Third division step:

Divide the leading term of the new dividend [tex]\(11x\)[/tex] by the leading term of the divisor [tex]\(x\)[/tex]. This gives [tex]\(11\)[/tex].

Multiply [tex]\(11\)[/tex] by [tex]\((x - 2)\)[/tex] to get [tex]\(11x - 22\)[/tex].

* Subtract [tex]\(11x - 22\)[/tex] from [tex]\(11x\)[/tex]:
[tex]\[ 11x - (11x - 22) = 11x - 11x + 22 = 22 \][/tex]

Now we have completed the division:

[tex]\[ \frac{x^3 + 6x^2 - 5x}{x - 2} = x^2 + 8x + 11 + \frac{22}{x - 2} \][/tex]

In the requested form, the solution is:

[tex]\[ \frac{x^3 + 6x^2 - 5x}{x - 2} = x^2 + 8x + 11 + \frac{22}{x - 2} \][/tex]

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