To solve this problem, we'll look at the specific values held by each of the '2's in California's population and then determine how many times the value of the first '2' is compared to the third '2'. The population of California in 2021 is 39,538,223.
1. Identify the position and value of the first '2':
- The first '2' appears in the millions place.
- Specifically, it is in the seventh position from the right: `39,528,223`.
- The value of this '2' is 2,000,000 since it is in the millions place (2 × 1,000,000).
2. Identify the position and value of the third '2':
- The third '2' appears in the tens place.
- Specifically, it is in the eighth position from the right: `39,538,22_3`.
- The value of this '2' is 20 since it is in the tens place (2 × 10).
3. Compare the values of the first and third '2':
- The value of the first '2' (in the millions place) is 2,000,000.
- The value of the third '2' (in the tens place) is 20.
4. Determine how many times the value of the first '2' is compared to the value of the third '2':
- We calculate the ratio by dividing the value of the first '2' by the value of the third '2'.
- [tex]\(\frac{2,000,000}{20} = 100,000\)[/tex]
Therefore, the value of the first '2' is 100,000 times as great as the value of the third '2'.
