Two sides of a triangle measure 4 and 6. Which inequality shows all the possible lengths of the third side, [tex]x[/tex]?

A. [tex]\frac{2}{3} \ \textless \ x \ \textless \ 24[/tex]
B. [tex]4 \ \textless \ x \ \textless \ 6[/tex]
C. [tex]2 \ \textless \ x \ \textless \ 10[/tex]
D. [tex]3 \ \textless \ x \ \textless \ 12[/tex]



Answer :

To determine the possible lengths of the third side [tex]\( x \)[/tex] of a triangle where the other two sides measure 4 and 6, we can use the triangle inequality theorem, which states the following conditions must be satisfied for any triangle:

1. The sum of the lengths of any two sides must be greater than the length of the third side.

For sides [tex]\( a = 4 \)[/tex], [tex]\( b = 6 \)[/tex], and [tex]\( c = x \)[/tex], this gives us the following three inequalities:

1. [tex]\( 4 + 6 > x \)[/tex]
2. [tex]\( 4 + x > 6 \)[/tex]
3. [tex]\( 6 + x > 4 \)[/tex]

Let's analyze each of these in detail:

1. [tex]\( 4 + 6 > x \)[/tex] simplifies to [tex]\( 10 > x \)[/tex] or [tex]\( x < 10 \)[/tex]
2. [tex]\( 4 + x > 6 \)[/tex] simplifies to [tex]\( x > 2 \)[/tex]
3. [tex]\( 6 + x > 4 \)[/tex] simplifies to [tex]\( x > -2 \)[/tex], but this condition is always true if [tex]\( x > 2 \)[/tex], so we don't need to consider it separately.

Combining the two relevant inequalities, we have:

[tex]\[ 2 < x < 10 \][/tex]

So, the possible lengths for the third side [tex]\( x \)[/tex] are those that satisfy the inequality [tex]\( 2 < x < 10 \)[/tex].

Hence, the correct choice is:

C) [tex]\( 2 < x < 10 \)[/tex]