Answer :
Sure, let's complete the standard multiplication algorithm for the given numbers [tex]$52 \times 0.27$[/tex].
1. Rewrite the problem:
[tex]\[ 52 \times 0.27 \][/tex]
2. Ignore the decimal point temporarily and multiply 52 by 27.
Write 52 and 27 in long multiplication format:
```
52
× 27
```
3. Multiply 52 by 7 (the units digit of 27):
```
52
× 7
-----
364 (Since 52 7 = 364)
```
4. Multiply 52 by 20 (the tens digit of 27, shifted one place to the left):
```
52
×20
-----
1040 (Since 52 20 = 1040)
```
5. Add the two results to get the combined result:
```
364
+1040
------
1404
```
6. Adjust for the decimal point. Since 0.27 has two decimal places, we need to place the decimal point two places from the right in the product:
```
1404 → 14.04
```
The final result of multiplying 52 by 0.27 is:
[tex]\[ 14.04 \][/tex]
So, by following the standard multiplication algorithm, the product of [tex]$52 \times 0.27$[/tex] is 14.04.
1. Rewrite the problem:
[tex]\[ 52 \times 0.27 \][/tex]
2. Ignore the decimal point temporarily and multiply 52 by 27.
Write 52 and 27 in long multiplication format:
```
52
× 27
```
3. Multiply 52 by 7 (the units digit of 27):
```
52
× 7
-----
364 (Since 52 7 = 364)
```
4. Multiply 52 by 20 (the tens digit of 27, shifted one place to the left):
```
52
×20
-----
1040 (Since 52 20 = 1040)
```
5. Add the two results to get the combined result:
```
364
+1040
------
1404
```
6. Adjust for the decimal point. Since 0.27 has two decimal places, we need to place the decimal point two places from the right in the product:
```
1404 → 14.04
```
The final result of multiplying 52 by 0.27 is:
[tex]\[ 14.04 \][/tex]
So, by following the standard multiplication algorithm, the product of [tex]$52 \times 0.27$[/tex] is 14.04.