The ground level, how long will it take to reach -270 m?

5. Raju finishes [tex]\frac{1}{4}[/tex] part of a work in 1 hour. How much part of the work will be finished in [tex]3 \frac{1}{5}[/tex] hours?



Answer :

Sure, let’s solve this problem step by step.

Raju finishes [tex]\(\frac{1}{4}\)[/tex] part of the work in 1 hour. We need to find out how much part of the work he will finish in [tex]\(3 \frac{1}{5}\)[/tex] hours.

1. Understand the task: Raju finishes [tex]\(\frac{1}{4}\)[/tex] part of the work in 1 hour. So the first step is to express [tex]\(3 \frac{1}{5}\)[/tex] hours as an improper fraction.

2. Convert mixed number to an improper fraction:
- [tex]\(3 \frac{1}{5}\)[/tex] can be converted by:
[tex]\[ 3 \frac{1}{5} = 3 + \frac{1}{5} = \frac{15}{5} + \frac{1}{5} = \frac{16}{5} \][/tex]
So, [tex]\(3 \frac{1}{5}\)[/tex] hours is [tex]\(\frac{16}{5}\)[/tex] hours.

3. Relate time to work done:
- Since Raju completes [tex]\(\frac{1}{4}\)[/tex] of the work in 1 hour, he completes [tex]\(\frac{1}{4} \times \frac{16}{5}\)[/tex] of the work in [tex]\( \frac{16}{5} \)[/tex] hours.

4. Multiply to find the work done:
[tex]\[ \frac{1}{4} \times \frac{16}{5} = \frac{16}{4 \times 5} = \frac{16}{20} = \frac{4}{5} \][/tex]

So, in [tex]\(3 \frac{1}{5}\)[/tex] hours, Raju will have finished [tex]\(\frac{4}{5}\)[/tex] or [tex]\(0.8\)[/tex] part of the work.