Harmony Family Access
Assignment List
Assignment Player
SCSC Bookmarks
PrIDE. Fusion - Goo
BHG IDEAS MATH
rspicero09

CONNECTING CONCEPTS

Point [tex]$S$[/tex] is between points [tex]$R$[/tex] and [tex]$T$[/tex] on [tex]$\overline{R T}$[/tex]. Use the information to write an equation in terms of [tex]$x$[/tex]. Then solve the equation, and find [tex]$R S, S T$[/tex] and [tex]$R T$[/tex].

Given:
[tex]\[ R S = 2x + 10, \][/tex]
[tex]\[ S T = x - 4, \][/tex]
[tex]\[ R T = 21. \][/tex]

Write the equation:
[tex]\[ 2x + 10 + x - 4 = 21. \][/tex]



Answer :

Sure, I can guide you through the solution in a detailed, step-by-step manner:

1. Understand the problem:
- We are given three line segments: [tex]\( RS \)[/tex], [tex]\( ST \)[/tex], and [tex]\( RT \)[/tex].
- The point [tex]\( S \)[/tex] is between points [tex]\( R \)[/tex] and [tex]\( T \)[/tex].
- The lengths of these segments are given in terms of [tex]\( x \)[/tex]:
[tex]\[ RS = 2x + 10, \quad ST = x - 4, \quad RT = 21 \][/tex]

2. Form an equation based on the given information:
- Since point [tex]\( S \)[/tex] is between [tex]\( R \)[/tex] and [tex]\( T \)[/tex], the length [tex]\( RT \)[/tex] is the sum of lengths [tex]\( RS \)[/tex] and [tex]\( ST \)[/tex]. Hence, we can write:
[tex]\[ RS + ST = RT \][/tex]
- Substituting the given expressions for [tex]\( RS \)[/tex], [tex]\( ST \)[/tex], and [tex]\( RT \)[/tex], we get:
[tex]\[ (2x + 10) + (x - 4) = 21 \][/tex]

3. Simplify the equation:
- Combine like terms:
[tex]\[ 2x + x + 10 - 4 = 21 \][/tex]
- Simplify further:
[tex]\[ 3x + 6 = 21 \][/tex]

4. Solve for [tex]\( x \)[/tex]:
- Subtract 6 from both sides:
[tex]\[ 3x = 15 \][/tex]
- Divide both sides by 3:
[tex]\[ x = 5 \][/tex]

5. Find the lengths of [tex]\( RS \)[/tex], [tex]\( ST \)[/tex], and [tex]\( RT \)[/tex]:
- Substitute [tex]\( x = 5 \)[/tex] into the expression for [tex]\( RS \)[/tex]:
[tex]\[ RS = 2x + 10 = 2(5) + 10 = 10 + 10 = 20 \][/tex]
- Substitute [tex]\( x = 5 \)[/tex] into the expression for [tex]\( ST \)[/tex]:
[tex]\[ ST = x - 4 = 5 - 4 = 1 \][/tex]
- Since [tex]\( RT = 21 \)[/tex] is already given and is the sum of [tex]\( RS \)[/tex] and [tex]\( ST \)[/tex], verify:
[tex]\[ RT = RS + ST = 20 + 1 = 21 \][/tex]

6. Summarize the results:
- The solution for [tex]\( x \)[/tex] is [tex]\( x = 5 \)[/tex].
- The lengths of the segments are:
[tex]\[ RS = 20, \quad ST = 1, \quad RT = 21 \][/tex]

So, the equation formed is [tex]\( 3x + 6 = 21 \)[/tex], solving this we find [tex]\( x = 5 \)[/tex]. Substituting [tex]\( x \)[/tex] back, we get [tex]\( RS = 20 \)[/tex], [tex]\( ST = 1 \)[/tex], and the total length [tex]\( RT = 21 \)[/tex] matches the given value.