Each year, a group of 150 Alaskan wolves has an average birth rate of [tex]15\%[/tex] and an average death rate of [tex]37\%[/tex] per year. Which function could be used to predict when there will be 25 wolves in this group?

[tex]\[
\begin{array}{l}
150\left((1.15)^t-(0.37)^t\right)=25 \\
150(1.15-0.63)^t=25 \\
150(1.15-0.37)^t=25 \\
\left.t-(0.63)^t\right)=25
\end{array}
\][/tex]



Answer :

Let's analyze the problem step-by-step to determine which function could be used to predict when there will be 25 wolves in this group and solve for the time [tex]\( t \)[/tex].

### Step 1: Understanding the Population Dynamics
1. Initial Population: The initial population of the Alaskan wolves is 150.
2. Birth Rate: The average birth rate is [tex]\(15\%\)[/tex] per year.
3. Death Rate: The average death rate is [tex]\(37\%\)[/tex] per year.

### Step 2: Determine the Net Growth Rate
To find the net growth rate, we subtract the death rate from the birth rate:
[tex]\[ \text{Net Growth Rate} = 15\% - 37\% = -22\% \][/tex]
Since the net growth rate is [tex]\(-22\%\)[/tex], the population decreases by [tex]\(22\%\)[/tex] each year.

### Step 3: Populating the Exponential Decay Model
The appropriate model for this population decrease can be represented as:
[tex]\[ P(t) = P_0 \times (1 + r)^t \][/tex]
where:
- [tex]\(P(t)\)[/tex] is the population at time [tex]\(t\)[/tex].
- [tex]\(P_0\)[/tex] is the initial population (150 wolves).
- [tex]\(r\)[/tex] is the net growth rate [tex]\((-22\%\)[/tex] or [tex]\(-0.22\)[/tex]).
- [tex]\(t\)[/tex] is the time in years.

Since [tex]\( r = -0.22 \)[/tex], the base of the exponential function becomes [tex]\(1 - 0.22 = 0.78\)[/tex].

### Step 4: Setting Up the Equation
We need to find out when the population will be 25 wolves. Thus, we set up the equation:
[tex]\[ 150 \times (0.78)^t = 25 \][/tex]

### Step 5: Solving the Equation
To solve for [tex]\(t\)[/tex]:
1. First, isolate [tex]\( (0.78)^t \)[/tex]:
[tex]\[ (0.78)^t = \frac{25}{150} \][/tex]
[tex]\[ (0.78)^t = \frac{1}{6} \][/tex]

2. Now take the natural logarithm of both sides to solve for [tex]\( t \)[/tex]:
[tex]\[ \ln((0.78)^t) = \ln\left(\frac{1}{6}\right) \][/tex]
Using the property of logarithms [tex]\( \ln(a^b) = b \ln(a) \)[/tex]:
[tex]\[ t \ln(0.78) = \ln\left(\frac{1}{6}\right) \][/tex]

3. Finally, solve for [tex]\( t \)[/tex]:
[tex]\[ t = \frac{\ln\left(\frac{1}{6}\right)}{\ln(0.78)} \][/tex]

### Step 6: Calculation (Numerically Solving)
Solving this numerically (we already have the result given in the problem):
[tex]\[ t \approx 7.211 \][/tex]

### Conclusion
The function we used to predict the population and the time it takes for the population to decline to 25 wolves is:
[tex]\[ 150 \times (0.78)^t = 25 \][/tex]
And solving this equation gives us [tex]\( t \approx 7.211 \)[/tex] years. Thus, it will take approximately 7.211 years for the group of 150 Alaskan wolves to decrease to 25 wolves with the given birth and death rates.