Answer :

Ryan2
[tex] x^{2} +10x+34=0\\ \\ \Delta=10^2-4.1.34=100-136=-36\\ \\ \boxed{x=\frac{-10\pm\sqrt{-36}}{2}=\frac{-10 \pm6i}{2}=-5\pm3i}[/tex]
kate200468
[tex]x^2+10x+34=0\\\\x^2+2\cdotx\cdot5+5^2+9=0\\\\(x+5)^2=-9\ \ \ \Rightarrow\ \ \ no\ real\ solution\\\\(x+5)^2=9\cdot i^2\ \ \ \Rightarrow\ \ \ ( x+5=3i\ \ \ \ \ \ \ or\ \ \ \ \ \ \ \ x+5=-3i)\\\\x_1=-5+3i,\ \ \ \ \ x_2=-5-3i\ \ \ \rightarrow\ \ \ two\ complex\ numbers\ solution[/tex]

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