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Putting value of x=3 in eq. (3)
x+y=5
3+y=5
y=2
Hence, the solution is x = 3, y = 2.
Exercise 5.2 (1,2)
Solve the following system of simultaneous linear equations by elimination method:
1. (x+y=5
x-y=3
2. (1) 11x-8y=27
(ii) 3x-2y=19
4x+y=18
(iii) 4x-3y=18
6x + 7y = 4
(iii) 5x + 4y = 4
(ii) x-4=4(y+2)
3x+5y=-7
3(x-2)=2y+20
x - 12y = 20
3
6
8
3. (9)+5y = 7;
= 7;
- +4y=5(x+0) (ii) 4x +
= 15; 6x -
-
= 14 (y = 0)
I
y
y
x-y
4. (1) 3-2(3x+4y) = x
(ii) 2x +
= 2
6
x-3 y-41
2x



Answer :

GinnyAnswer
To solve a system of simultaneous linear equations using the elimination method, you need to eliminate one variable by adding or subtracting the equations in the system to find the values of x and y that satisfy both equations. Let's look at each system provided and solve them step by step: 1. (x+y=5) (x-y=3) Adding the two equations: x + y = 5 x - y = 3 ----------------- 2x = 8 x = 4 Substitute x back into one of the original equations: 4 + y = 5 y = 1 Therefore, the solution is x = 4, y = 1. 2. (11x-8y=27) (3x-2y=19) Multiply the second equation by 4 to have the same coefficient for y: (11x-8y=27) (12x-8y=76) Subtract the second equation from the first: -x = -49 x = 49 Substitute x back into one of the original equations: 4(49) + y = 18 196 + y = 18 y = -178 Therefore, the solution is x = 49, y = -178. 3. (4x-3y=18) (6x + 7y = 4) Multiply the first equation by 7 and the second equation by 3 to eliminate y: (28x - 21y = 126) (18x + 21y = 12) Add the two equations: 46x = 138 x = 3 Substitute x back into one of the original equations: 4(3) - 3y = 18 12 - 3y = 18 -3y = 6 y = -2 Therefore, the solution is x = 3, y = -2. 4. (Not enough information provided to solve)

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