How many different three-digit numbers can be formed using the digits 4, 5, 3, 7, 6, and 8 with repetition
For example, 337 is allowed.
The number of different three-digit numbers is ☐ .



Answer :

Answer:

216

Step-by-step explanation:

If repetition is allowed, there is a formula known as permutation of repetition, n^r

n is known as the total number of objects in the given set, and r is the number of objects chosen in that set.

In this case n would be 6, and r would be 3

so the totoal number of different three digit numbers would be 6^3 = 216.

if repetition was not allowed though, the formula would be n!/(n-r)!

where n and r represent the same thing as before, but ! means factorial, so something like 3! would be 3x2x1, or 4! would be 4x3x2x1

So here the formula would translate to 6!/(6-3)! = 120

Hope that answers your questionf

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