Part 1 of 2

Solve the system of equations by graphing:

[tex]\[
\left\{
\begin{array}{l}
y = -x - 3 \\
y = -4x - 3
\end{array}
\right.
\][/tex]

Use the graphing tool to graph the system.



Answer :

To solve the system of equations by graphing, we need to graph each of the lines and find their intersection point.

The system of equations given is:
[tex]\[ \left\{ \begin{array}{l} y = -x - 3 \\ y = -4x - 3 \end{array} \right. \][/tex]

### Step-by-Step Solution

1. Graph the first equation [tex]\( y = -x - 3 \)[/tex]:

- Identify two points on the line by choosing values for [tex]\( x \)[/tex] and solving for [tex]\( y \)[/tex]:
- When [tex]\( x = 0 \)[/tex]:
[tex]\[ y = -0 - 3 = -3 \][/tex]
Thus, one point is [tex]\( (0, -3) \)[/tex].

- When [tex]\( x = 3 \)[/tex]:
[tex]\[ y = -3 - 3 = -6 \][/tex]
Thus, another point is [tex]\( (3, -6) \)[/tex].

- Plot these points and draw the line through them.

2. Graph the second equation [tex]\( y = -4x - 3 \)[/tex]:

- Similarly, choose two values for [tex]\( x \)[/tex] and solve for [tex]\( y \)[/tex]:
- When [tex]\( x = 0 \)[/tex]:
[tex]\[ y = -4(0) - 3 = -3 \][/tex]
Thus, one point is [tex]\( (0, -3) \)[/tex].

- When [tex]\( x = 1 \)[/tex]:
[tex]\[ y = -4(1) - 3 = -7 \][/tex]
Thus, another point is [tex]\( (1, -7) \)[/tex].

- Plot these points and draw the line through them.

3. Find the intersection point:

- By solving the equations simultaneously (setting [tex]\( -x - 3 = -4x - 3 \)[/tex]), we get:
[tex]\[ -x - 3 = -4x - 3 \][/tex]
Simplifying, we get:
[tex]\[ -x + 4x = 0 \\ 3x = 0 \\ x = 0 \][/tex]

- Substitute [tex]\( x = 0 \)[/tex] back into either equation to find [tex]\( y \)[/tex]:
[tex]\[ y = -0 - 3 = -3 \][/tex]

- The intersection point is [tex]\( (0, -3) \)[/tex].

4. Summary:
- The line [tex]\( y = -x - 3 \)[/tex] passes through the points [tex]\((0, -3)\)[/tex] and [tex]\((3, -6)\)[/tex].
- The line [tex]\( y = -4x - 3 \)[/tex] passes through the points [tex]\((0, -3)\)[/tex] and [tex]\((1, -7)\)[/tex].
- Both lines intersect at the point [tex]\((0, -3)\)[/tex].

[tex]\[ \boxed{(0, -3)} \][/tex]

By plotting these lines on a graph and visually identifying the intersection point, we confirm that the solution to the system of equations is [tex]\((0, -3)\)[/tex].

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