Solve: [tex]\((\sqrt{6})^{8x} = 216^{x-3}\)[/tex]

A. [tex]\(x = -9\)[/tex]
B. [tex]\(x = -3\)[/tex]
C. [tex]\(x = 0\)[/tex]
D. [tex]\(x = 4\)[/tex]



Answer :

To solve the equation [tex]\((\sqrt{6})^{8x} = 216^{(x-3)}\)[/tex], let's go through the steps methodically:

1. Understand the Form of Each Side

We begin by expressing both sides of the equation in terms of their base numbers:
[tex]\[ (\sqrt{6})^{8x} \quad \text{and} \quad 216^{x-3} \][/tex]

2. Simplify Bases

Recognize that [tex]\(\sqrt{6}\)[/tex] can be written as [tex]\(6^{1/2}\)[/tex], so the left-hand side becomes:
[tex]\[ (\sqrt{6})^{8x} = (6^{1/2})^{8x} = 6^{4x} \][/tex]
Next, use the fact that [tex]\(216\)[/tex] can be factored into prime factors:
[tex]\[ 216 = 6^3 \][/tex]
Therefore, the right-hand side becomes:
[tex]\[ 216^{x-3} = (6^3)^{x-3} = 6^{3(x-3)} = 6^{3x-9} \][/tex]

3. Equate Exponents

Since the bases are now the same, [tex]\(6\)[/tex], we can set the exponents equal to each other:
[tex]\[ 4x = 3(x-3) \][/tex]

4. Solve for [tex]\(x\)[/tex]

Now, solve the equation [tex]\(4x = 3(x-3)\)[/tex]:
[tex]\[ 4x = 3x - 9 \][/tex]
Subtract [tex]\(3x\)[/tex] from both sides:
[tex]\[ 4x - 3x = -9 \][/tex]
Simplify:
[tex]\[ x = -9 \][/tex]

5. Verify Against Options

Given multiple choice options are:
- [tex]\(x = -9\)[/tex]
- [tex]\(x = -3\)[/tex]
- [tex]\(x = 0\)[/tex]
- [tex]\(x = 4\)[/tex]

The solution [tex]\(x = -9\)[/tex] is one of the given choices.

Therefore, the correct answer is:
[tex]\[ \boxed{1} \][/tex]

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