[tex]\[
C_2H_5OH + 2O_2 \rightarrow 2CO_2 + 3H_2O + 1367\, \text{kJ}
\][/tex]

What is the ratio between ethanol and energy of the reaction?

[tex]\[ \square \text{ mole } C_2H_5OH \][/tex]
[tex]\[ \quad \text{kJ} \][/tex]



Answer :

To determine the ratio between ethanol and the energy of the reaction, we need to take a closer look at the balanced chemical equation provided:

[tex]\[ \text{C}_2\text{H}_5\text{OH} + 2 \text{O}_2 \rightarrow 2 \text{CO}_2 + 3 \text{H}_2\text{O} + 1367 \text{ kJ} \][/tex]

From this equation, we can see that:

1. One mole of ethanol (C₂H₅OH) reacts with two moles of oxygen (O₂) to produce two moles of carbon dioxide (CO₂), three moles of water (H₂O), and releases 1367 kJ of energy.

Therefore, the ratio between the moles of ethanol and the energy released in the reaction can be summarized as:

- 1 mole of C₂H₅OH corresponds to 1367 kJ of energy.

So, the ratio can be written as:

[tex]\[ 1 \text{ mole C}_2\text{H}_5\text{OH} : 1367 \text{ kJ} \][/tex]

Thus, the ratio is:

[tex]\[ \boxed{1} \text{ mole C}_2\text{H}_5\text{OH} \][/tex]
[tex]\[ \boxed{1367} \text{ kJ} \][/tex]