Use your data, the equation to the right, and the specific heat of water [tex]\left(4.184 \, J / g ^{\circ} C \right)[/tex] to compute the specific heat values of each metal. Use a calculator and round to the nearest hundredth place.

- Aluminum: [tex]c=\square \, J / g ^{\circ} C[/tex]
- Copper: [tex]c=\square \, J / g ^{\circ} C[/tex]
- Iron: [tex]c=\square \, J / g ^{\circ} C[/tex]
- Lead: [tex]c=\square \, J / g ^{\circ} C[/tex]

[tex]\[
\begin{tabular}{|c|c|c|c|c|}
\hline
& \text{Al} & \text{Cu} & \text{Fe} & \text{Pb} \\
\hline
m _{\text {water }}( g ) & 39.85 & 40.13 & 40.24 & 39.65 \\
\hline
m _{\text {metal }}( g ) & 11.98 & 12.14 & 12.31 & 12.46 \\
\hline
\Delta T _{\text {water }}\left(^{\circ} C \right) & 4.7 & 1.9 & 2.4 & 0.7 \\
\hline
\Delta T _{\text {metal }}\left(^{\circ} C \right) & -72.9 & -75.4 & -75.1 & -76.7 \\
\hline
\end{tabular}
\][/tex]

Be sure to record all of these values in the data table.

[tex]\[
c_{\text {metal }}=\frac{-c_{\text {water }} m_{\text {water }} \Delta T_{\text {water }}}{m_{\text {metal }} \Delta T_{\text {metal }}}
\][/tex]



Answer :

To calculate the specific heat values of each metal using the provided data and the equation [tex]\( c_{\text{metal}} = \frac{-c_{\text{water}} m_{\text{water}} \Delta T_{\text{water}}}{m_{\text{metal}} \Delta T_{\text{metal}}} \)[/tex], we'll follow these steps for each metal:

Given:
- [tex]\( c_{\text{water}} = 4.184 \, \text{J}/\text{g}^{\circ} \text{C} \)[/tex]

### Aluminum (Al)
1. Collect data:
- [tex]\( m_{\text{water}} = 39.85 \, \text{g} \)[/tex]
- [tex]\( m_{\text{metal}} = 11.98 \, \text{g} \)[/tex]
- [tex]\( \Delta T_{\text{water}} = 4.7 \, ^\circ \text{C} \)[/tex]
- [tex]\( \Delta T_{\text{metal}} = -72.9 \, ^\circ \text{C} \)[/tex]

2. Use the formula:
[tex]\[ c_{\text{metal}} = \frac{- 4.184 \times 39.85 \times 4.7}{11.98 \times -72.9} \][/tex]

3. Calculate:
[tex]\[ c_{\text{metal}} \approx 0.90 \, \text{J}/\text{g}^{\circ} \text{C} \][/tex]

### Copper (Cu)
1. Collect data:
- [tex]\( m_{\text{water}} = 40.13 \, \text{g} \)[/tex]
- [tex]\( m_{\text{metal}} = 12.14 \, \text{g} \)[/tex]
- [tex]\( \Delta T_{\text{water}} = 1.9 \, ^\circ \text{C} \)[/tex]
- [tex]\( \Delta T_{\text{metal}} = -75.4 \, ^\circ \text{C} \)[/tex]

2. Use the formula:
[tex]\[ c_{\text{metal}} = \frac{- 4.184 \times 40.13 \times 1.9}{12.14 \times -75.4} \][/tex]

3. Calculate:
[tex]\[ c_{\text{metal}} \approx 0.35 \, \text{J}/\text{g}^{\circ} \text{C} \][/tex]

### Iron (Fe)
1. Collect data:
- [tex]\( m_{\text{water}} = 40.24 \, \text{g} \)[/tex]
- [tex]\( m_{\text{metal}} = 12.31 \, \text{g} \)[/tex]
- [tex]\( \Delta T_{\text{water}} = 2.4 \, ^\circ \text{C} \)[/tex]
- [tex]\( \Delta T_{\text{metal}} = -75.1 \, ^\circ \text{C} \)[/tex]

2. Use the formula:
[tex]\[ c_{\text{metal}} = \frac{- 4.184 \times 40.24 \times 2.4}{12.31 \times -75.1} \][/tex]

3. Calculate:
[tex]\[ c_{\text{metal}} \approx 0.44 \, \text{J}/\text{g}^{\circ} \text{C} \][/tex]

### Lead (Pb)
1. Collect data:
- [tex]\( m_{\text{water}} = 39.65 \, \text{g} \)[/tex]
- [tex]\( m_{\text{metal}} = 12.46 \, \text{g} \)[/tex]
- [tex]\( \Delta T_{\text{water}} = 0.7 \, ^\circ \text{C} \)[/tex]
- [tex]\( \Delta T_{\text{metal}} = -76.7 \, ^\circ \text{C} \)[/tex]

2. Use the formula:
[tex]\[ c_{\text{metal}} = \frac{- 4.184 \times 39.65 \times 0.7}{12.46 \times -76.7} \][/tex]

3. Calculate:
[tex]\[ c_{\text{metal}} \approx 0.12 \, \text{J}/\text{g}^{\circ} \text{C} \][/tex]

### Final Answers:
- Aluminum (Al): [tex]\( c = 0.90 \, \text{J}/\text{g}^{\circ} \text{C} \)[/tex]
- Copper (Cu): [tex]\( c = 0.35 \, \text{J}/\text{g}^{\circ} \text{C} \)[/tex]
- Iron (Fe): [tex]\( c = 0.44 \, \text{J}/\text{g}^{\circ} \text{C} \)[/tex]
- Lead (Pb): [tex]\( c = 0.12 \, \text{J}/\text{g}^{\circ} \text{C} \)[/tex]

Make sure to record these computed values in the provided data table.