Answer :
A= b(1/c - 1/d)
A/b = 1/c -1/d
A/b + 1/d = 1/c
(A/b + 1/d) 1 = c
A/b = 1/c -1/d
A/b + 1/d = 1/c
(A/b + 1/d) 1 = c
Answer: c = b/(a + 1).
Step-by-step explanation:
a = b(1/c - 1/d)
Expand RHS by first finding LCM
a = b((d — c)/cd)
a = (bd — bc)/cd
Then cross multiply
acd = bd — cd
Collect the terms having c to the LHS
acd + cd = bd
Factorise cd out of LHS
( a+ 1)dc = bd
c = bd/(a + 1)d
c = b/(a + 1).