To rewrite the mass of the third object in scientific notation, let's follow these steps:
1. Identify the Given Mass:
The mass of the third object is [tex]\( 0.0000008 \)[/tex] grams.
2. Understand Scientific Notation:
Scientific notation is a way of writing numbers that are too large or too small to be conveniently written in decimal form. It is written as [tex]\( a \times 10^b \)[/tex], where [tex]\( a \)[/tex] is a number greater than or equal to 1 and less than 10, and [tex]\( b \)[/tex] is an integer.
3. Convert the Mass:
To convert [tex]\( 0.0000008 \)[/tex] to scientific notation:
- Move the decimal point so that there is only one non-zero digit to the left of the decimal point. This gives us [tex]\( 8.0 \)[/tex].
- Count the number of places the decimal point has been moved. In this case, it is 7 places to the right.
- Since we moved the decimal point to the right, the exponent [tex]\( b \)[/tex] will be [tex]\(-7\)[/tex].
Therefore, [tex]\( 0.0000008 \)[/tex] in scientific notation is [tex]\( 8.0 \times 10^{-7} \)[/tex].
4. Choose the Correct Answer:
From the given options:
- A. [tex]\( 8.0 \times 10^{-7} \)[/tex]
- B. [tex]\( 8.0 \times 10^{-5} \)[/tex]
- C. [tex]\( 8.0 \times 10^{-8} \)[/tex]
- D. [tex]\( 8.0 \times 10^{-6} \)[/tex]
The correct answer is [tex]\( 8.0 \times 10^{-7} \)[/tex], which corresponds to Option A.
Conclusion:
The mass of the third object in scientific notation is [tex]\( 8.0 \times 10^{-7} \)[/tex], so the correct answer is:
A. [tex]\( 8.0 \times 10^{-7} \)[/tex]
