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What is the simplest form of the expression representing this quotient?

[tex]\[
\frac{x^2 - 2x}{x^2 - 10x + 25} \div \frac{6x^2 - 12x}{x^2 - 25}
\][/tex]

[tex]\[
\boxed{}
\][/tex]

[tex]\[
\boxed{}
\][/tex]



Answer :

To simplify the given expression:
[tex]\[ \frac{x^2 - 2x}{x^2 - 10x + 25} \div \frac{6x^2 - 12x}{x^2 - 25} \][/tex]

we follow these steps:

1. Simplify each part of the given fractions:
- The numerator of the first fraction:
[tex]\[ x^2 - 2x = x(x - 2) \][/tex]
- The denominator of the first fraction:
[tex]\[ x^2 - 10x + 25 = (x - 5)^2 \][/tex]
- The numerator of the second fraction:
[tex]\[ 6x^2 - 12x = 6x(x - 2) \][/tex]
- The denominator of the second fraction:
[tex]\[ x^2 - 25 = (x - 5)(x + 5) \][/tex]

2. Rewrite the expression with the simplified parts:
[tex]\[ \frac{x(x - 2)}{(x - 5)^2} \div \frac{6x(x - 2)}{(x - 5)(x + 5)} \][/tex]

3. Convert the division of fractions into a multiplication by inverting the second fraction:
[tex]\[ \frac{x(x - 2)}{(x - 5)^2} \times \frac{(x - 5)(x + 5)}{6x(x - 2)} \][/tex]

4. Simplify by canceling out common factors:
- The [tex]\(x(x - 2)\)[/tex] terms cancel out in the numerator and denominator.
- The [tex]\((x - 5)\)[/tex] term cancels out with one of the [tex]\((x - 5)\)[/tex] terms in the denominator.

Thus, we are left with:
[tex]\[ \frac{x + 5}{6(x - 5)} \][/tex]

Therefore, the simplest form of the given expression is:
[tex]\[ \boxed{\frac{x+5}{6(x-5)}} \][/tex]

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