The reaction of 1-butene [tex]\(\left( CH_2=CHCH_2CH_3 \right)\)[/tex] and hydrogen [tex]\(\left( H_2 \right)\)[/tex] in the presence of a Pd catalyst produces:

A. 2-butene

B. 1-butyne

C. butane

D. methane and propane

E. two ethane molecules



Answer :

To solve this problem, it's important to understand the chemical reaction that occurs when 1-butene reacts with hydrogen in the presence of a palladium (Pd) catalyst.

1. Identify the Reactants and Reaction Conditions:
- The reactants are 1-butene ([tex]$CH_2=CHCH_2CH_3$[/tex]) and hydrogen ([tex]$H_2$[/tex]).
- The reaction is taking place in the presence of a palladium (Pd) catalyst.

2. Identify the Type of Reaction:
- This is a hydrogenation reaction. Hydrogenation involves the addition of hydrogen ([tex]$H_2$[/tex]) to molecules with carbon-carbon double bonds. A catalyst, such as palladium (Pd), is often required to facilitate this reaction.

3. Understand the Mechanism of the Reaction:
- In a hydrogenation reaction, hydrogen atoms add across the double bond of the 1-butene molecule.
- The double bond between carbon atoms in 1-butene will break, and each carbon atom will form a single bond with one of the hydrogen atoms from [tex]$H_2$[/tex].

4. Result of the Reaction:
- The conversion of a double bond to a single bond in 1-butene results in a fully saturated hydrocarbon.
- The molecule formed after hydrogenation will have no double bonds and is a straight-chain alkane.

5. Name the Product:
- The hydrogenated product of 1-butene is butane ([tex]$CH_3CH_2CH_2CH_3$[/tex]).

By following these steps and understanding the nature of hydrogenation reactions, the product of the reaction between 1-butene and hydrogen in the presence of a Pd catalyst is butane.

Thus, the correct answer is:

C. butane

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