Let's analyze the probabilities given different events described in the table.
1. Probability of a household having 1 pet and no children:
The probability is [tex]\(0.1582089552238806\)[/tex] or approximately [tex]\(15.82\%\)[/tex].
2. Probability of a household having 1 pet and children:
The probability is [tex]\(0.11343283582089553\)[/tex] or approximately [tex]\(11.34\%\)[/tex].
3. Probability of a household having 2 pets and children:
The probability is [tex]\(0.2537313432835821\)[/tex] or approximately [tex]\(25.37\%\)[/tex].
4. Probability of a household having 3 or more pets and children:
The probability is [tex]\(0.1373134328358209\)[/tex] or approximately [tex]\(13.73\%\)[/tex].
5. Probability of a household having 2 pets and no children:
The probability is [tex]\(0.12238805970149254\)[/tex] or approximately [tex]\(12.24\%\)[/tex].
6. Probability of a household having 3 or more pets and no children:
The probability is [tex]\(0.21492537313432836\)[/tex] or approximately [tex]\(21.49\%\)[/tex].
From these probabilities, we can compare the probability of having 1 pet and no children to the other given scenarios:
- It's less likely than [tex]\(25.37\%\)[/tex] (2 pets with children).
- It's moderately likely compared to [tex]\(21.49\%\)[/tex] (3 or more pets with no children).
- It's more likely than [tex]\(11.34\%\)[/tex] (1 pet with children), [tex]\(13.73\%\)[/tex] (3 or more pets with children), and [tex]\(12.24\%\)[/tex] (2 pets with no children).
Hence, the correct statement to complete is:
A customer is more likely to have 1 pet and no children than they are to have 1 pet and children, 2 pets and no children, and 3 or more pets and children.
Based on this, we should select:
A customer is more likely to have 1 pet and no children than they are to have 2 pets and no children.
