Let's solve the problem step by step:
1. Understand the reaction:
The chemical reaction given is:
[tex]\[ \text{SnO}_2 + 2 \text{H}_2 \rightarrow \text{Sn} + 2 \text{H}_2 \text{O} \][/tex]
According to the reaction, 1 mole of tin(IV) oxide (SnO[tex]\(_2\)[/tex]) reacts with 2 moles of hydrogen gas (H[tex]\(_2\)[/tex]) to produce 1 mole of tin metal (Sn) and 2 moles of water (H[tex]\(_2\)[/tex]O).
2. Given information:
We are given 0.74 moles of tin(IV) oxide.
3. Moles of tin metal produced:
From the reaction equation, we can see that 1 mole of tin(IV) oxide produces 1 mole of tin metal.
Thus, if we start with 0.74 moles of tin(IV) oxide, we will get an equal number of moles of tin metal.
Therefore, 0.74 moles of tin(IV) oxide will produce 0.74 moles of tin metal.
So, the correct answer is:
C. 0.74 moles
