Certainly! Let's go through the solution step-by-step.
To find the gravitational potential energy ([tex]\(E_g\)[/tex]) of the disc, we use the formula:
[tex]\[ E_g = mgh \][/tex]
where:
- [tex]\(m\)[/tex] is the mass of the disc,
- [tex]\(g\)[/tex] is the acceleration due to gravity,
- [tex]\(h\)[/tex] is the height above the ground.
Given:
- [tex]\(m = 0.2 \text{ kg}\)[/tex]
- [tex]\(h = 1.6 \text{ meters}\)[/tex]
- [tex]\(g = 10 \text{ m/s}^2\)[/tex]
Substitute these values into the formula:
[tex]\[ E_g = 0.2 \text{ kg} \times 10 \text{ m/s}^2 \times 1.6 \text{ meters} \][/tex]
Multiplying these values together:
[tex]\[ E_g = 0.2 \times 10 \times 1.6 \][/tex]
[tex]\[ E_g = 3.2 \text{ Joules} \][/tex]
Therefore, the gravitational potential energy of the disc is [tex]\(3.2\)[/tex] Joules.
