The [tex]$n$[/tex]th term of a geometric sequence is [tex]a_n = a_1 \cdot r^{n-1}[/tex], where [tex]a_1[/tex] is the first term and [tex]r[/tex] is the common ratio.

Identify [tex]a_1[/tex] and [tex]r[/tex] for each geometric sequence.

1. [tex]1, 3, 9, 27, \ldots[/tex]
[tex]\[a_1 = \square \][/tex]
[tex]\[r = \square \][/tex]

2. [tex]8, 4, 2, 1, \ldots[/tex]
[tex]\[a_1 = \square \][/tex]
[tex]\[r = \square \][/tex]

3. [tex]4, -16, 64, -256, \ldots[/tex]
[tex]\[a_1 = \square \][/tex]
[tex]\[r = \square \][/tex]



Answer :

To identify the first term ([tex]\(a_1\)[/tex]) and the common ratio ([tex]\(r\)[/tex]) for each given geometric sequence, we follow this method.

### Sequence 1: [tex]\(1, 3, 9, 27, \ldots\)[/tex]

1. First Term ([tex]\(a_1\)[/tex]): The first term of the sequence is the initial term given, which is 1.
2. Common Ratio ([tex]\(r\)[/tex]): The common ratio is found by dividing the second term by the first term.
[tex]\[ r = \frac{3}{1} = 3 \][/tex]

Thus, for the first sequence:
[tex]\[ a_1 = 1, \quad r = 3.0 \][/tex]

### Sequence 2: [tex]\(8, 4, 2, 1, \ldots\)[/tex]

1. First Term ([tex]\(a_1\)[/tex]): The first term of the sequence is the initial term given, which is 8.
2. Common Ratio ([tex]\(r\)[/tex]): The common ratio is found by dividing the second term by the first term.
[tex]\[ r = \frac{4}{8} = 0.5 \][/tex]

Thus, for the second sequence:
[tex]\[ a_1 = 8, \quad r = 0.5 \][/tex]

### Sequence 3: [tex]\(4, -16, 64, -256, \ldots\)[/tex]

1. First Term ([tex]\(a_1\)[/tex]): The first term of the sequence is the initial term given, which is 4.
2. Common Ratio ([tex]\(r\)[/tex]): The common ratio is found by dividing the second term by the first term.
[tex]\[ r = \frac{-16}{4} = -4 \][/tex]

Thus, for the third sequence:
[tex]\[ a_1 = 4, \quad r = -4.0 \][/tex]

Summarizing all the sequences, we get:

- For the sequence [tex]\(1, 3, 9, 27, \ldots\)[/tex]:
[tex]\[ a_1 = 1, \quad r = 3.0 \][/tex]
- For the sequence [tex]\(8, 4, 2, 1, \ldots\)[/tex]:
[tex]\[ a_1 = 8, \quad r = 0.5 \][/tex]
- For the sequence [tex]\(4, -16, 64, -256, \ldots\)[/tex]:
[tex]\[ a_1 = 4, \quad r = -4.0 \][/tex]