To solve the problem, let’s break it into two parts:
### Part 1: Finding the Elapsed Time for Trial B
The elapsed time is the difference between the final time and the initial time.
Given:
- Initial time for Trial B ([tex]\( t_{initial,B} \)[/tex]) = 1.5 seconds
- Final time for Trial B ([tex]\( t_{final,B} \)[/tex]) = 4.5 seconds
Elapsed time ([tex]\( t_{elapsed,B} \)[/tex]) is calculated as:
[tex]\[ t_{elapsed,B} = t_{final,B} - t_{initial,B} \][/tex]
[tex]\[ t_{elapsed,B} = 4.5 \, \text{s} - 1.5 \, \text{s} \][/tex]
[tex]\[ t_{elapsed,B} = 3.0 \, \text{s} \][/tex]
So, the elapsed time for Trial B is 3.0 seconds.
### Part 2: Finding the Average Speed for Trial B
The average speed is calculated by dividing the total distance traveled by the elapsed time.
Given:
- Distance traveled for Trial B ([tex]\( d_B \)[/tex]) = 4.0 meters
- Elapsed time for Trial B ([tex]\( t_{elapsed,B} \)[/tex]) = 3.0 seconds (from Part 1)
Average speed ([tex]\( v_{average,B} \)[/tex]) is calculated as:
[tex]\[ v_{average,B} = \frac{d_B}{t_{elapsed,B}} \][/tex]
[tex]\[ v_{average,B} = \frac{4.0 \, \text{m}}{3.0 \, \text{s}} \][/tex]
[tex]\[ v_{average,B} = 1.333 \, \text{m/s} \][/tex]
So, the average speed for Trial B is 1.333 m/s.
### Summary
- The elapsed time for Trial B is 3.0 seconds.
- The average speed for Trial B is 1.333 m/s.
