Find the equation that best represents the following word problem:

In a certain freshman class, the number of girls is 83 less than twice the number of boys. The total number of students in that freshman class is 259. How many boys and girls are in that class?

[tex]\[
\begin{array}{l}
\text{Let } b \text{ be the number of boys.} \\
\text{The number of girls is } 2b - 83. \\
\text{The total number of students is } b + (2b - 83) = 259. \\
\end{array}
\][/tex]

So, the equation is:
[tex]\[
3b - 83 = 259
\][/tex]



Answer :

To solve this word problem, let's break it down step-by-step and set up the correct equation.

1. Understanding the Problem:

- Let [tex]\( b \)[/tex] represent the number of boys in the class.
- The number of girls is 83 less than twice the number of boys.
- The total number of students in the class is 259.

2. Setting up the Equation:

We know that the total number of students is the sum of boys and girls:
[tex]\[ b + (\text{number of girls}) = 259 \][/tex]

According to the problem, the number of girls is 83 less than twice the number of boys:
[tex]\[ \text{number of girls} = 2b - 83 \][/tex]

Now, substitute this expression into the total number of students equation:
[tex]\[ b + (2b - 83) = 259 \][/tex]

3. Solving the Equation:

Simplify the equation:
[tex]\[ b + 2b - 83 = 259 \][/tex]

Combine like terms:
[tex]\[ 3b - 83 = 259 \][/tex]

Add 83 to both sides to isolate the term with [tex]\( b \)[/tex]:
[tex]\[ 3b = 259 + 83 \][/tex]
[tex]\[ 3b = 342 \][/tex]

Divide both sides by 3 to solve for [tex]\( b \)[/tex]:
[tex]\[ b = \frac{342}{3} \][/tex]
[tex]\[ b = 114 \][/tex]

4. Finding the Number of Girls:

Substitute [tex]\( b = 114 \)[/tex] back into the expression for the number of girls:
[tex]\[ \text{number of girls} = 2b - 83 \][/tex]
[tex]\[ \text{number of girls} = 2(114) - 83 \][/tex]
[tex]\[ \text{number of girls} = 228 - 83 \][/tex]
[tex]\[ \text{number of girls} = 145 \][/tex]

So, the number of boys in the class is 114, and the number of girls is 145.

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