Check all that apply.

[tex]\sec \theta[/tex] is undefined for [tex]\theta =[/tex]

A. [tex]\frac{\pi}{2}[/tex]
B. [tex]\frac{3 \pi}{2}[/tex]
C. 0
D. [tex]\pi[/tex]



Answer :

To determine where the secant function, [tex]\(\sec \theta\)[/tex], is undefined, we need to look at the definition of [tex]\(\sec \theta\)[/tex]. The secant function is defined as:

[tex]\[ \sec \theta = \frac{1}{\cos \theta} \][/tex]

This function is undefined whenever the denominator, [tex]\(\cos \theta\)[/tex], is equal to 0, because division by zero is undefined. Hence, we need to find the values of [tex]\(\theta\)[/tex] where [tex]\(\cos \theta = 0\)[/tex].

Let's examine each of the given angles:

A. [tex]\(\theta = \frac{\pi}{2}\)[/tex]

[tex]\[ \cos \left(\frac{\pi}{2}\right) = 0 \][/tex]

Since [tex]\(\cos \left(\frac{\pi}{2}\right) = 0\)[/tex], [tex]\(\sec \left(\frac{\pi}{2}\right) = \frac{1}{0}\)[/tex], which is undefined.

B. [tex]\(\theta = \frac{3\pi}{2}\)[/tex]

[tex]\[ \cos \left(\frac{3\pi}{2}\right) = 0 \][/tex]

Since [tex]\(\cos \left(\frac{3\pi}{2}\right) = 0\)[/tex], [tex]\(\sec \left(\frac{3\pi}{2}\right) = \frac{1}{0}\)[/tex], which is also undefined.

C. [tex]\(\theta = 0\)[/tex]

[tex]\[ \cos(0) = 1 \][/tex]

Since [tex]\(\cos(0) = 1\)[/tex], [tex]\(\sec(0) = \frac{1}{1} = 1\)[/tex], which is defined.

D. [tex]\(\theta = \pi\)[/tex]

[tex]\[ \cos(\pi) = -1 \][/tex]

Since [tex]\(\cos(\pi) = -1\)[/tex], [tex]\(\sec(\pi) = \frac{1}{-1} = -1\)[/tex], which is also defined.

After analyzing these angles, we conclude that [tex]\(\sec \theta\)[/tex] is undefined for:

- A. [tex]\(\frac{\pi}{2}\)[/tex]
- B. [tex]\(\frac{3 \pi}{2}\)[/tex]

Thus, the correct answers are:

A. [tex]\(\frac{\pi}{2}\)[/tex]

B. [tex]\(\frac{3 \pi}{2}\)[/tex]