Answer:
To find out after how many seconds does the fishing lure hits the water, we need to solve the equation h=-16t^2 + 24t + 4.
Setting h = 0, as the lure hits the water when the height is 0, we get the following equation:
0 = -16t^2 + 24t + 4
Solving for t using the quadratic formula, we get:
t = (-24 +/- sqrt(24^2 - 4(-16)(4))) / (2(-16))
t = (-24 +/- sqrt(576