A block is pulled by a force of [tex]$177 \, \text{N}$[/tex] directed at an [tex]$85.0^{\circ}$[/tex] angle from the horizontal. What is the x-component of the force acting on the block?

[tex]\overrightarrow{F_X} = \, ? \, \text{N}[/tex]



Answer :

To find the x-component of the force acting on a block when a force is applied at an angle from the horizontal, we use the cosine component of the force vector along the x-axis. The following steps outline the solution:

1. Understand the given values:
- The magnitude of the force, [tex]\( F \)[/tex], is 177 N.
- The angle, [tex]\( \theta \)[/tex], at which the force is applied from the horizontal is [tex]\( 85.0^{\circ} \)[/tex].

2. Convert the angle from degrees to radians:
Angles are often more conveniently expressed in radians for calculations involving trigonometric functions. The conversion from degrees to radians is done by multiplying the degree measure by [tex]\( \frac{\pi}{180} \)[/tex].
[tex]\[ \theta_{\text{radians}} = 85.0^{\circ} \times \frac{\pi}{180} \][/tex]
This gives:
[tex]\[ \theta_{\text{radians}} = 1.4835298641951802 \text{ radians} \][/tex]

3. Calculate the x-component of the force:
The x-component of the force can be found using the formula [tex]\( F_X = F \cos(\theta) \)[/tex], where [tex]\( F \)[/tex] is the magnitude of the force and [tex]\( \theta \)[/tex] is the angle in radians.
[tex]\[ F_X = 177 \cos(1.4835298641951802) \][/tex]

4. Evaluate the cosine function and multiply by the force:
[tex]\[ F_X = 177 \times \cos(1.4835298641951802) \][/tex]

5. Result:
The calculated x-component of the force is:
[tex]\[ \overrightarrow{F_X} = 15.42656646633549 \text{ N} \][/tex]

Thus, the x-component of the force acting on the block is approximately [tex]\( 15.43 \text{ N} \)[/tex].